11b^2-22=6b

Solution for 11b^2-22=6b equation:

11b^2-22=6b

We move all terms to the left:

11b^2-22-(6b)=0

a = 11; b = -6; c = -22;
Δ = b2-4ac
Δ = -62-4·11·(-22)
Δ = 1004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1004}=\sqrt{4*251}=\sqrt{4}*\sqrt{251}=2\sqrt{251}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{251}}{2*11}=\frac{6-2\sqrt{251}}{22}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{251}}{2*11}=\frac{6+2\sqrt{251}}{22}
$